Expanding the left side of the equation, we get:
X(X-3) - (X+2)(X+1= X^2 - 3X - (X^2 + 3X + 2= X^2 - 3X - X^2 - 3X - = -6X - 2
Now, we have the equation:
-6X - 2 = 10
Adding 2 to both sides:
-6X = 12
Dividing by -6:
X = -2
Therefore, the solution to the equation X(X-3)-(x+2)(X+1) = 10 is X = -2.
Expanding the left side of the equation, we get:
X(X-3) - (X+2)(X+1
= X^2 - 3X - (X^2 + 3X + 2
= X^2 - 3X - X^2 - 3X -
= -6X - 2
Now, we have the equation:
-6X - 2 = 10
Adding 2 to both sides:
-6X = 12
Dividing by -6:
X = -2
Therefore, the solution to the equation X(X-3)-(x+2)(X+1) = 10 is X = -2.