2.(m^1/3+2n^1/2)^2-(m^1/3-2n^1/2)2 3.(m^1/4-n^1/2)(m^1/4+n^1/2) 4.(m^1/2+n)(m-m^1/2n+n^2)

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вопрос

(m^1/3 + 2n^1/2)^2 - (m^1/3 - 2n^1/2)^2
Expanding the expression using the formula (a + b)^2 = a^2 + 2ab + b^2, we get:

= m^(2/3) + 4mn^(1/3) + 4n - (m^(2/3) - 4mn^(1/3) + 4n)
= m^(2/3) + 4mn^(1/3) + 4n - m^(2/3) + 4mn^(1/3) - 4n
= 8mn^(1/3)

(m^1/4 - n^1/2)(m^1/4 + n^1/2)
Using the difference of squares formula (a - b)(a + b) = a^2 - b^2, we get:

= m^(1/2) - n - n
= m^(1/2) - 2n

(m^1/2 + n)(m - m^1/2n + n^2)
Expanding the expression, we get:

= m^3 + mn - m^1/2n + n^2 - m^1/2n - m^(1/2)n + n
= m^3 + mn - 2m^(1/2)n + n^2