(y+4)-(y-1)=6y; 3p-1-(p+3)=1; 6x-(7x-12)=101; 20x=19-(3+12x); (13x-15)-(9+6x)=-3x; 12-(4x-18)=(36+4x)+(18-6x).

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вопрос

y + 4 - y + 1 = 6y
4 + 1 = 6y
5 = 6y
y = 5/6

3p - 1 - p - 3 = 1
2p - 4 = 1
2p = 5
p = 5/2

6x - (7x - 12) = 101
6x - 7x + 12 = 101
-x + 12 = 101
-x = 89
x = -89

20x = 19 - (3 + 12x)
20x = 19 - 15 - 12x
20x = 4 - 12x
32x = 4
x = 4/32
x = 1/8

(13x - 15) - (9 + 6x) = -3x
13x - 15 - 9 - 6x = -3x
13x - 15 - 9 + 3x = 0
16x - 24 = 0
16x = 24
x = 24/16
x = 3/2

12 - (4x - 18) = (36 + 4x) + (18 - 6x)
12 - 4x + 18 = 36 + 4x + 18 - 6x
30 - 4x = 54 - 2x
-4x + 2x = 54 - 30
-2x = 24
x = -24/2
x = -12