To find the derivative of the function, we will use the chain rule and the power rule:
F'(x) = 3(-x^2+2x)^2 (-2x + 2) + 4(x-3)^3= 3(-x^2 + 2x)^2 (-2x + 2) + 4(x-3)^3= 3(-x^2 + 2x)^2 (-2x + 2) + 4*(x-3)^3
Therefore, the derivative of the function F(x) is:
F'(x) = 3(-x^2 + 2x)^2 (-2x + 2) + 4*(x-3)^3
To find the derivative of the function, we will use the chain rule and the power rule:
F'(x) = 3(-x^2+2x)^2 (-2x + 2) + 4(x-3)^3
= 3(-x^2 + 2x)^2 (-2x + 2) + 4(x-3)^3
= 3(-x^2 + 2x)^2 (-2x + 2) + 4*(x-3)^3
Therefore, the derivative of the function F(x) is:
F'(x) = 3(-x^2 + 2x)^2 (-2x + 2) + 4*(x-3)^3