To solve this quadratic equation, we need to first recognize that it is in the form of a quadratic equation. In other words, it is a polynomial equation where the highest degree of the variable (in this case, x) is 2.
The equation is in the form of ax^2 + bx + c = 0, where a = 12, b = 5, and c = -2.
To solve for x, we can use the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
Substitute the values of a, b, and c into the formula:
x = [-5 ± √(5^2 - 412(-2))] / 2*1 x = [-5 ± √(25 + 96)] / 2 x = [-5 ± √121] / 2 x = (-5 ± 11) / 24
Therefore, the solutions for x are x = (11-5) / 24 = 6/24 = 1/ x = (-11-5) / 24 = -16 / 24 = -2/3
So, the solutions to the quadratic equation 12x^2 + 5x - 2 = 0 are x = 1/4 and x = -2/3.
To solve this quadratic equation, we need to first recognize that it is in the form of a quadratic equation. In other words, it is a polynomial equation where the highest degree of the variable (in this case, x) is 2.
The equation is in the form of ax^2 + bx + c = 0, where a = 12, b = 5, and c = -2.
To solve for x, we can use the quadratic formula:
x = [-b ± √(b^2 - 4ac)] / 2a
Substitute the values of a, b, and c into the formula:
x = [-5 ± √(5^2 - 412(-2))] / 2*1
x = [-5 ± √(25 + 96)] / 2
x = [-5 ± √121] / 2
x = (-5 ± 11) / 24
Therefore, the solutions for x are
x = (11-5) / 24 = 6/24 = 1/
x = (-11-5) / 24 = -16 / 24 = -2/3
So, the solutions to the quadratic equation 12x^2 + 5x - 2 = 0 are x = 1/4 and x = -2/3.