(х+1)^2(х^2-8х+15)/3-х

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First, we need to expand the numerator.

(х+1)^2 = (x+1)(x+1) = x^2 + 2x + 1

Now, we can multiply this by the other binomial:

(x^2 + 2x + 1)(x^2 - 8x + 15) = x^4 - 8x^3 + 15x^2 + 2x^3 - 16x^2 + 30x + x^2 - 8x + 15 = x^4 - 6x^3 - x^2 + 6x + 15

So, the numerator becomes:

x^4 - 6x^3 - x^2 + 6x + 15

Now, divide this by 3x:

(x^4 - 6x^3 - x^2 + 6x + 15) / (3 - x)

We can continue by performing polynomial long division or synthetic division to simplify further. Let me know if you need help with that.