(1/a+2/b+a/b)*ab/(a*a-b*b)+2(b-a)=

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вопрос

(1/a + 2/b + a/b)ab/(aa - b*b) + 2(b - a)

= (1/a + 2/b + a/b)*(ab)/(a^2 - b^2) + 2(b - a)

= (b + 2a + a^2/b)*(ab)/(a + b)(a - b) + 2(b - a)

= (ab + 2a^2 + a^3/b)/(a - b) + 2(b - a)

= (a^3 + 2a^2b + ab^2)/(ab - b^2) + 2(b - a)

= ((a + b)(a^2 + 2ab + b^2))/(b(a - b)) + 2(b - a)

= (a^2 + 2ab + b^2)/b + 2(b - a)

= (a + b)^2/b + 2(b - a)

= (a + b)(a + b)/b + 2(b - a)

= (a + b)*(a + b)/b + 2(b - a)

= (a^2 + 2ab + b^2)/b + 2(b - a)

= a^2/b + 2ab/b + b^2/b + 2b - 2a

= a + 2a + b + 2b - 2a

= 4b