1)3(a+1)+a-4(2+a)<0 2)(a-2)2-a(a-4)>0

Предыдущий
вопрос Следующий
вопрос

1) Simplifying the inequality:

3(a+1) + a - 4(2+a) < 0
3a + 3 + a - 8 - 4a < 0
-a - 5 < 0
-a < 5
a > -5

Therefore, the solution set for the inequality is: a > -5

2) Simplifying the inequality:

(a - 2)^2 - a(a - 4) > 0
(a^2 - 4a + 4) - (a^2 - 4a) > 0
4 > 0

Since 4 is always greater than 0, the solution set for this inequality is all real numbers except when the denominator is 0.

Therefore, the solution set for the inequality is all real numbers.