To solve this system of equations, we can substitute the second equation into the first equation:
x² + (1/2)x² - 5 = 100
Combining like terms:
(3/2)x² - 5 = 100
Add 5 to both sides:
(3/2)x² = 105
Divide by 3/2 on both sides:
x² = 105 * 2 / 3x² = 70
Taking the square root of both sides:
x = ±√70
Now, substitute the value of x back into the second equation to solve for y:
y = (1/2)(√70)² - 10y = (1/2)(70) - 10y = 35 - 10y = 25
Therefore, the solutions to the system of equations are x = ±√70 and y = 25.
To solve this system of equations, we can substitute the second equation into the first equation:
x² + (1/2)x² - 5 = 100
Combining like terms:
(3/2)x² - 5 = 100
Add 5 to both sides:
(3/2)x² = 105
Divide by 3/2 on both sides:
x² = 105 * 2 / 3
x² = 70
Taking the square root of both sides:
x = ±√70
Now, substitute the value of x back into the second equation to solve for y:
y = (1/2)(√70)² - 10
y = (1/2)(70) - 10
y = 35 - 10
y = 25
Therefore, the solutions to the system of equations are x = ±√70 and y = 25.