To solve this equation, we can set each factor equal to zero and solve for x:
1) 2cos(x) - 1 = 2cos(x) = cos(x) = 1/x = π/3, 5π/3
2) cos(2x) + 1 = cos(2x) = -2x = x = π/2
Therefore, the solutions to the equation are x = π/3, 5π/3, and π/2.
To solve this equation, we can set each factor equal to zero and solve for x:
1) 2cos(x) - 1 =
2cos(x) =
cos(x) = 1/
x = π/3, 5π/3
2) cos(2x) + 1 =
cos(2x) = -
2x =
x = π/2
Therefore, the solutions to the equation are x = π/3, 5π/3, and π/2.