To solve these systems of equations, we can use either substitution or elimination method. Let's solve each system separately:
Let's add the two equations together to eliminate y:
2x - y + 3x + y = 2 + 5x = 1x = 2
Now, substitute x = 2 back into one of the equations to solve for y2(2) - y = 4 - y = y = 2
Therefore, the solution to the first system is x = 2, y = 2.
Let's add the two equations together to eliminate y4x + y + 3x - y = 3 + 17x = 1x = 2
Now, substitute x = 2 back into one of the equations to solve for y4(2) + y = 8 + y = y = -5
Therefore, the solution to the second system is x = 2, y = -5.
Let's subtract the second equation from the first to eliminate x(4x - 3y) - (4x - 7y) = 3 - (-54y = y = 2
Now, substitute y = 2 back into one of the equations to solve for x4x - 3(2) = 4x - 6 = 4x = x = 9/4
Therefore, the solution to the third system is x = 9/4, y = 2.
To solve these systems of equations, we can use either substitution or elimination method. Let's solve each system separately:
2x - y =3x + y = 8
Let's add the two equations together to eliminate y:
2x - y + 3x + y = 2 +
5x = 1
x = 2
Now, substitute x = 2 back into one of the equations to solve for y
2(2) - y =
4 - y =
y = 2
Therefore, the solution to the first system is x = 2, y = 2.
4x + y =3x - y = 11
Let's add the two equations together to eliminate y
4x + y + 3x - y = 3 + 1
7x = 1
x = 2
Now, substitute x = 2 back into one of the equations to solve for y
4(2) + y =
8 + y =
y = -5
Therefore, the solution to the second system is x = 2, y = -5.
4x - 3y =4x - 7y = -5
Let's subtract the second equation from the first to eliminate x
(4x - 3y) - (4x - 7y) = 3 - (-5
4y =
y = 2
Now, substitute y = 2 back into one of the equations to solve for x
4x - 3(2) =
4x - 6 =
4x =
x = 9/4
Therefore, the solution to the third system is x = 9/4, y = 2.