4x^2 + x + 3 = 0, 8x^2 + x + 1 = 0.

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Let's solve the first equation
4x^2 + x + 3 = 0

Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

where a = 4, b = 1, and c = 3

x = (-1 ± √(1^2 - 443)) / 2*
x = (-1 ± √(1 - 48)) /
x = (-1 ± √(-47)) /
x = (-1 ± √47i) / 8

Therefore, the solutions for the first equation are
x = (-1 + √47i) / 8 and x = (-1 - √47i) / 8

Now let's solve the second equation
8x^2 + x + 1 = 0

Using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a

where a = 8, b = 1, and c = 1

x = (-1 ± √(1^2 - 481)) / 2*
x = (-1 ± √(1 - 32)) / 1
x = (-1 ± √(-31)) / 1
x = (-1 ± √31i) / 16

Therefore, the solutions for the second equation are
x = (-1 + √31i) / 16 and x = (-1 - √31i) / 16