To solve the first equation 12x^2 - 2x = 0, we can factor out x from both terms:
2x(6x - 1) = 0
Setting each factor to 0, we get:
2x = 0 or 6x - 1 = x = 0 or x = 1/6
Therefore, the solutions to the first equation are x = 0 and x = 1/6.
To solve the second equation 5x^2 - 4x + 3 = 0, we can use the quadratic formula:
x = (-(-4) ± √((-4)^2 - 453)) / (25x = (4 ± √(16 - 60)) / 1x = (4 ± √(-44)) / 1x = (4 ± 2√11i) / 1x = (2 ± √11*i) / 5
Therefore, the solutions to the second equation are x = (2 + √11i) / 5 and x = (2 - √11i) / 5.
To solve the first equation 12x^2 - 2x = 0, we can factor out x from both terms:
2x(6x - 1) = 0
Setting each factor to 0, we get:
2x = 0 or 6x - 1 =
x = 0 or x = 1/6
Therefore, the solutions to the first equation are x = 0 and x = 1/6.
To solve the second equation 5x^2 - 4x + 3 = 0, we can use the quadratic formula:
x = (-(-4) ± √((-4)^2 - 453)) / (25
x = (4 ± √(16 - 60)) / 1
x = (4 ± √(-44)) / 1
x = (4 ± 2√11i) / 1
x = (2 ± √11*i) / 5
Therefore, the solutions to the second equation are x = (2 + √11i) / 5 and x = (2 - √11i) / 5.