2(5x-7)(1=x)=0 4*(8+7x)-x=8

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The given equation is not quite correct. There is a mistake in the first equation. Let's correct it and then we can solve both equations:

1) 2(5x - 7)(1 - x) = 0
Expanding the expression:
2(5x - 7 - 5x^2 + 7x) = 0
2(5 - 7 - 5x^2 + 7x) = 0
2(-2 - 5x^2 + 7x) = 0
-4 - 10x^2 + 14x = 0
-10x^2 + 14x - 4 = 0
Dividing by -2:
5x^2 - 7x + 2 = 0

Now we can solve the quadratic equation 5x^2 - 7x + 2 = 0 by factoring:
5x^2 - 5x - 2x + 2 = 0
5x(x - 1) - 2(x - 1) = 0
(5x - 2)(x - 1) = 0

Setting each factor to zero gives:
5x - 2 = 0 -> 5x = 2 -> x = 2/5
x - 1 = 0 -> x = 1

Therefore, the solutions to the first equation are x = 2/5 and x = 1.

2) 4(8 + 7x) - x = 8
Expanding the expression:
32 + 28x - x = 8
31 + 27x = 8
27x = -23
x = -23/27

Therefore, the solution to the second equation is x = -23/27.