(log3x-log3y=2) / (x-4y=5)

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вопрос Следующий
вопрос

To solve this system of equations, we first need to isolate one of the variables in one of the equations and then substitute it into the other equation to solve for the other variable.

Given
1) log3x - log3y =
2) x - 4y = 5

From equation (1), we can rewrite it as
log3(x/y) = 2

This can be rewritten in exponential form as
3^2 = x/y

Therefore, x = 9y

Now we can substitute x = 9y into equation (2):

9y - 4y =
5y =
y = 1

Now that we have found the value of y, we can substitute it back into equation (1) to solve for x:

log3x - log3(1) =
log3x =
x = 3^
x = 9

Therefore, the solution to the system of equations is x = 9, y = 1.