Log3 (x+8)+ log3(x-4)

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To combine the logarithms into a single logarithm, we can use the properties of logarithms.

loga(b) + loga(c) = loga(bc)

So, applying this property to the given expression:

log3(x+8) + log3(x-4)
= log3((x+8)(x-4))
= log3(x^2 + 4x - 32)

Therefore, log3(x+8) + log3(x-4) is equivalent to log3(x^2 + 4x - 32).