56/(36/k-2)=8 (k/5+3)*6=48

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вопрос

To solve for k, we will first simplify each equation separately.

Equation 1: 56/(36/k-2) = 8
To simplify, we can multiply both sides by (36/k-2) to get rid of the fraction:
56 = 8(36/k-2)
56 = 288/k - 16
72 = 288/k
k = 288/72
k = 4

Equation 2: (k/5 + 3)6 = 48
First, simplify:
(k/5 + 3)6 = 48
6k/5 + 18 = 48

Now, isolate the k variable:
6k/5 = 48 - 18
6k/5 = 30
6k = 150
k = 150/6
k = 25

Thus, the value of k that satisfies both equations is k = 25.