(x+3/2-y)^3 * (x+3/y-2)^-2 (3a/2b)^3 * 16b^5/9a^4

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вопрос

(x + 3/2 - y)^3 (x + 3/y - 2)^(-2) (3a/2b)^3 * (16b^5/9a^4)

First, expand and simplify the expression:

(x + 3/2 - y)^3 = (x + 3/2 - y)(x + 3/2 - y)(x + 3/2 - y)
Expanding this will result in:
x^3 + (3/2)^3 + y^3 + 3x^2(3/2) + 3x(3/2)^2 + 3x^2(-y) + 3(3/2)(-y) + 3x(-y)^2

(x + 3/y - 2)^(-2) = 1/(x + 3/y - 2)^2

(3a/2b)^3 = (3a)^3 / (2b)^3 = 27a^3 / 8b^3

(16b^5 / 9a^4) = 16b^5 / 9a^4

Now, multiply the expressions together:

(x^3 + (3/2)^3 + y^3 + 3x^2(3/2) + 3x(3/2)^2 + 3x^2(-y) + 3(3/2)(-y) + 3x(-y)^2) 1/(x + 3/y - 2)^2 27a^3 / 8b^3 * 16b^5 / 9a^4

This is the final expression that is a result of multiplying the given expressions.

Please let me know if you have any other questions.