To expand the expression (Х-3)(Х-5)(Х+3)(Х-5), we can use the distributive property and FOIL method.
(Х-3)(Х-5)(Х+3)(Х-5) = (Х^2 - 5Х - 3Х + 15)(Х^2 - 5Х + 3Х - 15) = (Х^2 - 8Х + 15)(Х^2 - 2Х - 15) = Х^2 Х^2 - 2Х Х^2 - 15 Х^2 - 8Х Х^2 + 16Х - 15 - 15Х + 30 = Х^4 - 2Х^3 - 15Х^2 - 8Х^3 + 16Х - 15 - 15Х + 30 = Х^4 - 10Х^3 - 30Х^2 + Х - 15
Therefore, the expanded form of (Х-3)(Х-5)(Х+3)(Х-5) is Х^4 - 10Х^3 - 30Х^2 + Х - 15.
To expand the expression (Х-3)(Х-5)(Х+3)(Х-5), we can use the distributive property and FOIL method.
(Х-3)(Х-5)(Х+3)(Х-5)
= (Х^2 - 5Х - 3Х + 15)(Х^2 - 5Х + 3Х - 15)
= (Х^2 - 8Х + 15)(Х^2 - 2Х - 15)
= Х^2 Х^2 - 2Х Х^2 - 15 Х^2 - 8Х Х^2 + 16Х - 15 - 15Х + 30
= Х^4 - 2Х^3 - 15Х^2 - 8Х^3 + 16Х - 15 - 15Х + 30
= Х^4 - 10Х^3 - 30Х^2 + Х - 15
Therefore, the expanded form of (Х-3)(Х-5)(Х+3)(Х-5) is Х^4 - 10Х^3 - 30Х^2 + Х - 15.