-x^2-2x+7=0 X^3-5x^2-x+5=0

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Since these are two separate equations, we need to solve them separately.

First, let's solve the quadratic equation -x^2 - 2x + 7 = 0.

To solve the quadratic equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / 2a

In this equation, a = -1, b = -2, and c = 7. Plugging these values into the formula, we get:
x = (2 ± √((-2)^2 - 4(-1)7)) / (2*(-1))
x = (2 ± √(4 + 28)) / -2
x = (2 ± √32) / -2
x = (2 ± 4√2) / -2
x = -1 ± 2√2

Therefore, the solutions to the quadratic equation are x = -1 + 2√2 and x = -1 - 2√2.

Now, let's solve the cubic equation x^3 - 5x^2 - x + 5 = 0.

To solve a cubic equation, we typically use numerical methods or advanced mathematical methods. One way is to try different values of x in the equation to find an approximate root. Another approach is to use the Rational Root Theorem to find rational roots, if they exist.

Using the Rational Root Theorem, the possible rational roots of the cubic equation are the factors of the constant term 5 divided by the factors of the leading coefficient 1. In this case, the possible rational roots are ±1, ±5.

By testing these values in the equation, we find that x = 1 is a root of the equation. By dividing the cubic equation by (x - 1), we can find the remaining quadratic equation and solve for the other roots.
After dividing, we get x^2 - 4x - 5 = 0, which can be factored as (x - 5)(x + 1) = 0.
Therefore, the other roots of the cubic equation are x = 5 and x = -1.

In conclusion, the solutions to the cubic equation x^3 - 5x^2 - x + 5 = 0 are x = 1, 5, and -1.