(x+3)(x-3)-(x-3)(x+2)-5=6x-7

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вопрос

To solve this equation, we can first simplify each side of the equation:

Left side:
(x+3)(x-3) - (x-3)(x+2) - 5
Expanding each term, we get:
(x^2 - 3x + 3x - 9) - (x^2 + 2x - 3x - 6) - 5
(x^2 - 9) - (x^2 - 6) - 5
x^2 - 9 - x^2 + 6 - 5
-9 + 6 - 5
-8

Right side:
6x - 7

Therefore, the equation simplifies to:
-8 = 6x - 7

Adding 7 to both sides, we get:
-8 + 7 = 6x
-1 = 6x

Dividing by 6, we find:
x = -1/6

Therefore, the solution to the equation is x = -1/6.