3(x-1)=2(x+2); 3(x-5)-2(x+4)=-5x+1;

Предыдущий
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вопрос

Let's solve each equation:

1) 3(x-1)=2(x+2)
Distribute on both sides:
3x - 3 = 2x + 4
Subtract 2x from both sides:
x - 3 = 4
Add 3 to both sides:
x = 7

Therefore, the solution to the first equation is x = 7.

2) 3(x-5) - 2(x+4) = -5x + 1
Distribute on both sides:
3x - 15 - 2x - 8 = -5x + 1
Combine like terms:
x - 23 = -5x + 1
Add 5x to both sides:
6x - 23 = 1
Add 23 to both sides:
6x = 24
Divide by 6:
x = 4

Therefore, the solution to the second equation is x = 4.