(2x+3)(3x+1)-10=11x+20

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вопрос

Let's first expand the left side of the equation:

(2x + 3)(3x + 1) - 1
= 2x 3x + 2x 1 + 3 3x + 3 1 - 1
= 6x^2 + 2x + 9x + 3 - 1
= 6x^2 + 11x - 7

Now, let's compare this to the right side of the equation:

11x + 20

Since the two sides are equal, we can set them equal to each other:

6x^2 + 11x - 7 = 11x + 20

Now, let's simplify the equation further:

6x^2 + 11x - 7 - 11x - 20 =
6x^2 - 27 = 0

Now, we can solve for x by factoring or using the quadratic formula:

6x^2 - 27 =
6x^2 = 2
x^2 = 27/
x^2 = 4.
x = ±√4.
x = ±2.121

Therefore, the solutions are x = 2.121 or x = -2.121.