Lg3 (2x -4)=lg3 (x+7)

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вопрос

To solve this equation, we need to isolate the variable on one side of the equation.

First, we can rewrite the equation using the properties of logarithms:

lg3 (2x - 4) = lg3 (x + 7)

This equation represents that the logarithm of (2x - 4) to the base 3 is equal to the logarithm of (x + 7) to the base 3.

Since the base of the logarithms is the same, we can drop the logarithms:

2x - 4 = x + 7

Now, we can solve for x by isolating the variable on one side:

2x - x = 7 + 4
x = 11

Therefore, the solution to the equation lg3 (2x - 4) = lg3 (x + 7) is x = 11.