(x^2-x)^2-12(x^2-x)=0

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To solve this equation, we can first simplify it by factoring out (x^2-x) from both terms:

(x^2-x)((x^2-x) - 12) = 0

Now, we can further simplify by factoring out (x^2-x) from (x^2-x) - 12:

(x^2-x)(x(x-1) - 12) = 0

Now we have two factors: (x^2-x) = 0 and (x(x-1) - 12) = 0

For (x^2-x) = 0:
x(x-1) = 0
x = 0 or x = 1

For (x(x-1) - 12) = 0:
x^2 - x - 12 = 0
(x-4)(x+3) = 0
x = 4 or x = -3

Therefore, the solutions to the equation are x = 0, x = 1, x = 4, and x = -3.