To find the values of x and y, we can create a system of equations using the given information:
1) x + y = 42) x * y = 15
From equation 1, we can rearrange it to get y = 48 - x.
Substitute this expression for y into equation 2:
x * (48 - x) = 148x - x^2 = 1x^2 - 48x + 15 = 0
Now we can solve this quadratic equation for x using the quadratic formula:
x = [48 ± sqrt((48)^2 - 4115)] / x = [48 ± sqrt(2304 - 60)] / x = [48 ± sqrt(2244)] / x = [48 ± 47.43] / 2
So, x = 48 + 47.43, x = 48 - 47.43
x = 95.43 / 2 or x = 0.57 / 2
Therefore, x = 47.715 or x = 0.285.
To find the values of y, we substitute these values of x back into y = 48 - x:
If x = 47.715, then y = 48 - 47.715 = 0.285If x = 0.285, then y = 48 - 0.285 = 47.715.
So, x = 47.715, y = 0.28or x = 0.285, y = 47.715.
To find the values of x and y, we can create a system of equations using the given information:
1) x + y = 4
2) x * y = 15
From equation 1, we can rearrange it to get y = 48 - x.
Substitute this expression for y into equation 2:
x * (48 - x) = 1
48x - x^2 = 1
x^2 - 48x + 15 = 0
Now we can solve this quadratic equation for x using the quadratic formula:
x = [48 ± sqrt((48)^2 - 4115)] /
x = [48 ± sqrt(2304 - 60)] /
x = [48 ± sqrt(2244)] /
x = [48 ± 47.43] / 2
So, x = 48 + 47.43, x = 48 - 47.43
x = 95.43 / 2 or x = 0.57 / 2
Therefore, x = 47.715 or x = 0.285.
To find the values of y, we substitute these values of x back into y = 48 - x:
If x = 47.715, then y = 48 - 47.715 = 0.285
If x = 0.285, then y = 48 - 0.285 = 47.715.
So, x = 47.715, y = 0.28
or x = 0.285, y = 47.715.