|x+1|+|x+2|=2
There are two cases to consider:
Case 1: x+1 > 0 and x+2 > 0In this case, the equation simplifies to:x+1 + x+2 = 22x + 3 = 22x = -1x = -1/2
Case 2: x+1 < 0 and x+2 < 0In this case, the equation simplifies to:-(x+1) - (x+2) = 2-x - 1 - x - 2 = 2-2x - 3 = 2-2x = 5x = -5/2
Therefore, the solutions to the equation |x+1|+|x+2|=2 are x = -1/2 and x = -5/2.
|x+1|+|x+2|=2
There are two cases to consider:
Case 1: x+1 > 0 and x+2 > 0
In this case, the equation simplifies to:
x+1 + x+2 = 2
2x + 3 = 2
2x = -1
x = -1/2
Case 2: x+1 < 0 and x+2 < 0
In this case, the equation simplifies to:
-(x+1) - (x+2) = 2
-x - 1 - x - 2 = 2
-2x - 3 = 2
-2x = 5
x = -5/2
Therefore, the solutions to the equation |x+1|+|x+2|=2 are x = -1/2 and x = -5/2.