5arccos 1/2+3 arccos(-√2/2)

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вопрос

To evaluate this expression, we first need to find the angle values for both arccos functions.

arccos(1/2) = π/3 (60 degrees)
arccos(-√2/2) = 3π/4 (135 degrees)

Now we can substitute these values into the expression:

5(π/3) + 3(3π/4)
= 5π/3 + 9π/4
= (20π + 27π)/12
= 47π/12

Therefore, the value of the expression is 47π/12.