(х⁴+х²+1)(х⁴+х²+2)=12

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вопрос

Expanding the given equation:

(x^4 + x^2 + 1)(x^4 + x^2 + 2) = 12

Expanding the left side:

x^8 + 2x^6 + 2x^6 + 4x^4 + x^4 + x^2 + 2x^6 + 2x^4 + 2x^2 + x^4 + x^2 + 2 = 12

Simplifying:

x^8 + 4x^6 + 6x^4 + 3x^2 + 2 = 12

Rearranging terms:

x^8 + 4x^6 + 6x^4 + 3x^2 - 10 = 0

This is the final quadratic equation formed by the given expression.