To solve this equation, we can break it down into two separate quadratic equations:
Let's denote:a = x^2 + 3xb = 3
Then the first quadratic equation becomes:a + 3 = 0a = -3
The second quadratic equation becomes:a + 1 = 0a = -1
Therefore, the solutions for x are the roots of the quadratic equations -3 and -1:x = (-3 - 3) / 2 = -6 / 2 = -3x = (-3 - 1) / 2 = -4 / 2 = -2
So the solutions for the given equation are x = -3 and x = -2.
To solve this equation, we can break it down into two separate quadratic equations:
Let's denote:
a = x^2 + 3x
b = 3
Then the first quadratic equation becomes:
a + 3 = 0
a = -3
The second quadratic equation becomes:
a + 1 = 0
a = -1
Therefore, the solutions for x are the roots of the quadratic equations -3 and -1:
x = (-3 - 3) / 2 = -6 / 2 = -3
x = (-3 - 1) / 2 = -4 / 2 = -2
So the solutions for the given equation are x = -3 and x = -2.