To solve this system of equations using the method of addition, we will first rewrite the equations in standard form:
1) 7x + 4y = 72) 3x + 2y = 32
Next, we will multiply Equation 2 by 2 so that the coefficients of y in both equations become the same:
1) 7x + 4y = 72) 6x + 4y = 64
Now, we will subtract Equation 2 from Equation 1:
(7x + 4y) - (6x + 4y) = 74 - 67x + 4y - 6x - 4y = 1x = 10
Now that we have found the value of x, we can substitute it back into either of the original equations to find the value of y. Let's use Equation 1:
7(10) + 4y = 770 + 4y = 74y = y = 1
Therefore, the solution to the system of equations is x = 10 and y = 1.
To solve this system of equations using the method of addition, we will first rewrite the equations in standard form:
1) 7x + 4y = 7
2) 3x + 2y = 32
Next, we will multiply Equation 2 by 2 so that the coefficients of y in both equations become the same:
1) 7x + 4y = 7
2) 6x + 4y = 64
Now, we will subtract Equation 2 from Equation 1:
(7x + 4y) - (6x + 4y) = 74 - 6
7x + 4y - 6x - 4y = 1
x = 10
Now that we have found the value of x, we can substitute it back into either of the original equations to find the value of y. Let's use Equation 1:
7(10) + 4y = 7
70 + 4y = 7
4y =
y = 1
Therefore, the solution to the system of equations is x = 10 and y = 1.