1)3х^2+5x=2; 2) -5x^2+x=0; 3)(x+7)(x-10) 0

Предыдущий
вопрос Следующий
вопрос

For the first equation 3х^2 + 5x = 2:
Rearrange the equation to the standard quadratic form ax^2 + bx + c = 0
3x^2 + 5x - 2 = 0

For the second equation -5x^2 + x = 0:
Rearrange the equation to the standard quadratic form ax^2 + bx + c = 0
-5x^2 + x = 0

For the third equation (x+7)(x-10) = 0:
Set each factor equal to zero and solve for x:
x + 7 = 0
x = -7

x - 10 = 0
x = 10

Therefore, the solutions for the third equation are x = -7 and x = 10.