To find the values of x that satisfy both inequalities, we can solve each inequality separately and then find the intersection of their solution sets.
1) 3 + 3x > 0 Subtracting 3 from both sides: 3x > -3 Dividing by 3: x > -1
2) 2 - 3x > 14 Subtracting 2 from both sides: -3x > 12 Dividing by -3 (note that dividing by a negative number requires flipping the inequality sign): x < -4
The solution set for the first inequality is x > -1 and for the second inequality is x < -4. To find the intersection of the solution sets, we look for the values of x that satisfy both conditions. So, the values of x that satisfy both inequalities are: -4 < x < -1
To find the values of x that satisfy both inequalities, we can solve each inequality separately and then find the intersection of their solution sets.
1) 3 + 3x > 0
Subtracting 3 from both sides:
3x > -3
Dividing by 3:
x > -1
2) 2 - 3x > 14
Subtracting 2 from both sides:
-3x > 12
Dividing by -3 (note that dividing by a negative number requires flipping the inequality sign):
x < -4
The solution set for the first inequality is x > -1 and for the second inequality is x < -4. To find the intersection of the solution sets, we look for the values of x that satisfy both conditions. So, the values of x that satisfy both inequalities are:
-4 < x < -1