1. (6у-1)(6у+1)-4у(9у+2)=-12. 4у(3у-1)-2у(6у+8)=53.5-3у-(4у-2у)=у-8-(у-1)

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вопрос

Expanding the first equation:

(36y^2 - 1) - (36y^2 + 8y) = -12
36y^2 - 1 - 36y^2 - 8y = -12
-8y - 1 = -12
-8y = -11
y = 11/8

Expanding the second equation:

4y(3y-1) - 2y(6y+8) = 53
12y^2 - 4y - 12y^2 - 16y = 53
-20y = 53
y = -53/20

Solving the third equation:

5 - 3y - 4y + 2y = y - 8 - y + 1
5 - 5y = -7
-5y = -12
y = 12/5

Thus, the values of y that satisfy the equations are y = 11/8, y = -53/20, and y = 12/5.