Y^3 - 6x^2 + 12x - 8 = 0, z^3 - 6y^2 + 12y - 8 =0,x^3 - 6z^2 + 12z - 8 =0

Предыдущий
вопрос Следующий
вопрос

To find the value of x, y, and z that satisfy all three equations, we can start by solving the first equation for x in terms of y and z. Then substitute this expression for x into the second equation to solve for y in terms of z, and finally substitute both expressions into the third equation to solve for z.

From the first equation:
Y^3 - 6x^2 + 12x - 8 = 0
x^2 - 12x + Y^3 + 8 = 0
Using the quadratic formula:
x = (12 ± √(144 - 4Y^3 - 32)) / 2
x = 6 ± √(4 - Y^3 + 2)
x = 6 ± √(6 - Y^3)

Now substitute x into the second equation:
z^3 - 6y^2 + 12y - 8 = 0
(6 ± √(6 - Y^3))^3 - 6y^2 + 12y - 8 = 0
(6 ± √(6 - Y^3))^3 - 6y^2 + 12y - 8 = 0

Substitute y and z back into the third equation to find the solution for z. We will reach a trajectory that will need a numerical computational strategy.