Given that the perimeter P is 4m and the length is 1/3 of the width, we can set up an equation to find the area.
Let the width be W and the length be L.
From the information givenP = 2(L + W) = 4L = W/3
Substitute L = W/3 into the perimeter equation2(W/3 + W) = 2W/3 + 2W = 2W + 6W = 18W = 1W = 1.5m
Now we can find the lengthL = W/3 = 1.5/3 = 0.5m
The area of the rectangle (S) is given byS = L x W = 0.5m x 1.5m = 0.75 square meters
Therefore, the area of the rectangle is 0.75 square meters.
Given that the perimeter P is 4m and the length is 1/3 of the width, we can set up an equation to find the area.
Let the width be W and the length be L.
From the information given
P = 2(L + W) = 4
L = W/3
Substitute L = W/3 into the perimeter equation
2(W/3 + W) =
2W/3 + 2W =
2W + 6W = 1
8W = 1
W = 1.5m
Now we can find the length
L = W/3 = 1.5/3 = 0.5m
The area of the rectangle (S) is given by
S = L x W = 0.5m x 1.5m = 0.75 square meters
Therefore, the area of the rectangle is 0.75 square meters.