Let the number of balls in the left hand be x and in the right hand be y. According to the given conditions, we have the following equations:
x = 2ny = 2m + 1x + 4 = 30y + 5 = 30
Solving the last two equations, we get:x = 30 - 4x = 26
Substitute the value of x in the first equation:26 = 2nn = 13
So, there are 26 balls in the left hand.
Let the number of balls in the left hand be x and in the right hand be y. According to the given conditions, we have the following equations:
x = 2n
y = 2m + 1
x + 4 = 30
y + 5 = 30
Solving the last two equations, we get:
x = 30 - 4
x = 26
Substitute the value of x in the first equation:
26 = 2n
n = 13
So, there are 26 balls in the left hand.