1) (x²-x)²-18(x²-x-2)+36=0 2)√(x²+3x-10=-x²-3x+10

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1) Let's simplify the first equation step by step:

(x²-x)² - 18(x²-x-2) +36 = 0
Expand the square term:
(x²-x)(x²-x) - 18(x²-x-2) +36 = 0
(x^4 - 2x^3 + x^2) - 18(x^2 - x - 2) + 36 = 0
x^4 - 2x^3 + x^2 - 18x^2 + 18x + 36 + 36 = 0
x^4 - 2x^3 - 17x^2 + 18x + 72 = 0

Therefore, the simplified form of the first equation is x^4 - 2x^3 - 17x^2 + 18x + 72 = 0.

2) Let's simplify the second equation:

√(x² + 3x - 10) = -x² - 3x + 10
Square both sides to eliminate the square root:
(x² + 3x - 10) = (-x² - 3x + 10)^2
(x² + 3x - 10) = (x^4 + 6x^3 + 13x^2 - 20x + 100)

Expand the right side:
x² + 3x - 10 = x^4 + 6x^3 + 13x^2 - 20x + 100

Rearrange the terms to get a polynomial equation in standard form:
x^4 + 6x^3 + 13x^2 - 20x + 100 - x^2 - 3x + 10 = 0
x^4 + 6x^3 + 12x^2 - 23x + 90 = 0

Therefore, the simplified form of the second equation is x^4 + 6x^3 + 12x^2 - 23x + 90 = 0.