Log(12) 2 + log(12) 75 = log(12) (275) = log(12) 150 = log(12) (12 12.5) = log(12) (12) + log(12) (12.5) = 1 + log(12.5) = 1 + log(10) 5 + log(10) 2 = 1 + log(10) 5 + log(10) 2 = 1 + 0.69897 + 0.30103 = 2.00000
Log(12) 2 + log(12) 75 = log(12) (275)
= log(12) 150
= log(12) (12 12.5)
= log(12) (12) + log(12) (12.5)
= 1 + log(12.5)
= 1 + log(10) 5 + log(10) 2
= 1 + log(10) 5 + log(10) 2
= 1 + 0.69897 + 0.30103
= 2.00000