To solve these equations, we first need to isolate the variable in each equation.
For the first equation:
1) mx = 20 To isolate the variable m, we divide both sides by x: m = 20/x
For the second equation:
2) (m+3)x = -18 To isolate the variable m, we first need to distribute the x: mx + 3x = -18 Next, we can substitute the value of m from the first equation into the second equation: (20/x)(x) + 3x = -18 20 + 3x = -18 Now, we can isolate x: 3x = -18 - 20 3x = -38 x = -38/3 x = -12.67
So, the solution for the system of equations is m = 20/x and x = -12.67.
To solve these equations, we first need to isolate the variable in each equation.
For the first equation:
1) mx = 20
To isolate the variable m, we divide both sides by x:
m = 20/x
For the second equation:
2) (m+3)x = -18
To isolate the variable m, we first need to distribute the x:
mx + 3x = -18
Next, we can substitute the value of m from the first equation into the second equation:
(20/x)(x) + 3x = -18
20 + 3x = -18
Now, we can isolate x:
3x = -18 - 20
3x = -38
x = -38/3
x = -12.67
So, the solution for the system of equations is m = 20/x and x = -12.67.