Mn(m-n)-(m во 2 степяни -n во 2 степяни )(2m+n)

Предыдущий
вопрос Следующий
вопрос

Mn(m-n) - (m^2 - n^2)(2m+n)

Expanding the second term using the difference of squares formula (a^2 - b^2 = (a+b)(a-b)):

Mn(m-n) - ((m+n)(m-n))(2m+n)

Now, simplify further:

Mn(m-n) - (m+n) (m-n) (2m+n)

Now, distribute:

Mn^2 - 2m^3n - 2n^3m - n^2m + m^2n

Combine like terms:

Mn^2 - 2m^3n - 2n^3m - n^2m + m^2n

Therefore, the final expression is:

Mn^2 - 2m^3n - 2n^3m - n^2m + m^2n