3x^2+4x=4 3x-1/x+2-7/2+x=7x^2-28/x^2-4+18/2-x

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вопрос

3x^2 + 4x - 4 = 0

Using the quadratic formula:
x = (-4 ± sqrt(4^2 - 43(-4)) / (2*3)
x = (-4 ± sqrt(16 + 48)) / 6
x = (-4 ± sqrt(64)) / 6
x = (-4 ± 8) / 6

Therefore, x = (-4 + 8) / 6 or x = (-4 - 8) / 6
x = 4/6 or x = -12/6
x = 2/3 or x = -2

This equation involves complex fractions and it would be best to simplify it before attempting to solve for x. Simplify the equation first, and then solve for x.