32-2целых45/47-3целых39/47+x-7целых41/47=22целых2/47

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вопрос

First, let's add the fractions on the left side of the equation to get a single fraction:

(32-2)/(45/47) - (3+39)/(47) + (x-7)/(41/47) = 22 2/47

(30)/(45/47) - (42)/(47) + (x-7)/(41/47) = 22 2/47

(30)/(45/47) - (42)/(47) + (x-7)/(41/47) = 22 2/47

(30 47)/45 - 42 + (41/47)(x-7) = (22*47 + 2)/47

141 - 42 + (41/47)*(x-7) = 22 + 2/47

99 + (41/47)*(x-7) = 22 + 2/47

Now, let's simplify the equation further:

(41/47)*(x-7) = 22 + 2/47 - 99

(41/47)*(x-7) = 22 + 2/47 - 4702/47

(41/47)*(x-7) = 22 - 4699/47

(41/47)*(x-7) = (1024/47)

Now we multiply throughout by 47 to clear the denominator:

41(x-7) = 1024

41x - 287 = 1024

41x = 1311

x = 1311 / 41

x = 31

Therefore, the value of x is 31.