To solve this equation, we need to use the properties of logarithms.
First, we can simplify the equation using the properties of logarithms:
Log3x - 2Log(1/3)x = 6Log3x - Log((1/3)x)^2 = 6Log3x - Log(x^2/9) = 6Log(3x / (x^2/9)) = 6Log(27 / x) = 6
Now we can rewrite this equation in exponential form:
27 / x = 10^627 = 10^6 * x27 = 1000000xx = 27 / 1000000x = 0.000027
Therefore, the solution to the equation Log3x - 2Log(1/3)x = 6 is x = 0.000027.
To solve this equation, we need to use the properties of logarithms.
First, we can simplify the equation using the properties of logarithms:
Log3x - 2Log(1/3)x = 6
Log3x - Log((1/3)x)^2 = 6
Log3x - Log(x^2/9) = 6
Log(3x / (x^2/9)) = 6
Log(27 / x) = 6
Now we can rewrite this equation in exponential form:
27 / x = 10^6
27 = 10^6 * x
27 = 1000000x
x = 27 / 1000000
x = 0.000027
Therefore, the solution to the equation Log3x - 2Log(1/3)x = 6 is x = 0.000027.