Y^4 - y^3 - 16y^2 + 16y = 0 9x^3 - 18x^2 - x + 2 = 0

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вопрос

To solve the equations:

Factor out a y from the equation:
y(y^3 - y^2 - 16y + 16) = 0

Factorize the remaining expression in the brackets:
y(y^2(y-1) -16(y-1)) = 0
y(y-1)(y^2-16) = 0

Setting each factor to zero:
y = 0, 1, -4, 4

Therefore, the solutions are y = 0, 1, -4, 4

This equation is not easily factorizable, so let's solve it using numerical methods like Newton's method or any root-finding algorithm.