а) sin110°-sin50° = 2cos(80°)sin(30°) = 2cos(80°)(1/2) = cos80°
б) cos110°+cos50° = 2cos(80°)cos(30°) = 2cos(80°)(√3/2) = √3cos80°
в) cos110°- cos50° = -2sin(80°)sin(30°) = -2sin(80°)(1/2) = -sin80°
а) sin110°-sin50° = 2cos(80°)sin(30°) = 2cos(80°)(1/2) = cos80°
б) cos110°+cos50° = 2cos(80°)cos(30°) = 2cos(80°)(√3/2) = √3cos80°
в) cos110°- cos50° = -2sin(80°)sin(30°) = -2sin(80°)(1/2) = -sin80°