There are a total of 30 chickens. Let's let x represent the number of chickens with 2 legs and y represent the number of chickens with 3 legs.
We know that each chicken has either 2 or 3 legs. So we can write the equations: x + y = 30 (total number of chickens) 2x + 3y = 72 (total number of legs)
From the first equation, we can rewrite it as x = 30 - y and substitute it into the second equation: 2(30 - y) + 3y = 72 60 - 2y + 3y = 72 60 + y = 72 y = 12
Therefore, there are 12 chickens with 3 legs. Answer: 12
There are a total of 30 chickens. Let's let x represent the number of chickens with 2 legs and y represent the number of chickens with 3 legs.
We know that each chicken has either 2 or 3 legs. So we can write the equations:
x + y = 30 (total number of chickens)
2x + 3y = 72 (total number of legs)
From the first equation, we can rewrite it as x = 30 - y and substitute it into the second equation:
2(30 - y) + 3y = 72
60 - 2y + 3y = 72
60 + y = 72
y = 12
Therefore, there are 12 chickens with 3 legs. Answer: 12