1)3x2+4x-15=0 2)5x2-11x+2=0

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вопрос

1) To solve the equation 3x^2 + 4x - 15 = 0, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a
where a = 3, b = 4, and c = -15.

Plugging in the values:
x = (-4 ± √(4^2 - 43(-15))) / 2*3
x = (-4 ± √(16 + 180)) / 6
x = (-4 ± √196) / 6
x = (-4 ± 14) / 6

There are two solutions:
x = (-4 + 14) / 6 = 10 / 6 = 5/3
x = (-4 - 14) / 6 = -18 / 6 = -3

Therefore, the solutions to the equation 3x^2 + 4x - 15 = 0 are x = 5/3 and x = -3.

2) To solve the equation 5x^2 - 11x + 2 = 0, we can use the quadratic formula with a = 5, b = -11, and c = 2.

Plugging in the values:
x = (11 ± √((-11)^2 - 452)) / 2*5
x = (11 ± √(121 - 40)) / 10
x = (11 ± √81) / 10
x = (11 ± 9) / 10

There are two solutions:
x = (11 + 9) / 10 = 20 / 10 = 2
x = (11 - 9) / 10 = 2 / 10 = 1/5

Therefore, the solutions to the equation 5x^2 - 11x + 2 = 0 are x = 2 and x = 1/5.