a⋅d = (2m - 4v) ⋅ (3m + 2v)a⋅d = 2m⋅3m + 2m⋅2v - 4v⋅3m - 4v⋅2va⋅d = 6m^2 + 4m⋅v - 12m⋅v - 8v^2a⋅d = 6m^2 - 8v^2a⋅d = 6(5)^2 - 8(5)^2a⋅d = 6(25) - 8(25)a⋅d = 150 - 200a⋅d = -50
Итак, скалярное произведение векторов a→ и d→ равно -50.
a⋅d = (2m - 4v) ⋅ (3m + 2v)
a⋅d = 2m⋅3m + 2m⋅2v - 4v⋅3m - 4v⋅2v
a⋅d = 6m^2 + 4m⋅v - 12m⋅v - 8v^2
a⋅d = 6m^2 - 8v^2
a⋅d = 6(5)^2 - 8(5)^2
a⋅d = 6(25) - 8(25)
a⋅d = 150 - 200
a⋅d = -50
Итак, скалярное произведение векторов a→ и d→ равно -50.