(7х-24):12+26=31; 144-(х÷11+21)×5=14; (105-(25+6х)×4)×30=150

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вопрос

Let's solve each equation separately:

1) (7x-24)/12 + 26 = 31
(7x-24)/12 = 31 - 26
(7x-24)/12 = 5
7x - 24 = 60
7x = 84
x = 12

2) 144 - (x/11 + 21) * 5 = 14
144 - 5(x/11 + 21) = 14
144 - 5x/11 - 105 = 14
39 - 5x/11 = 14
5x/11 = 25
5x = 275
x = 55

3) (105 - (25 + 6x) 4) 30 = 150
(105 - (25 + 6x) 4) = 5
(105 - (25 + 6x) 4) = 5/30
(105 - 4(25 + 6x)) = 1/6
105 - 100 - 24x = 1/6
5 - 24x = 1/6
-24x = 1/6 - 5
-24x = -29/6
x = 29/(6 * 24)
x = 29/144

Therefore, x = 12, 55, 29/144.